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- Added the leetcode problem and solution for 415
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‎README.md‎

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- [392 Is Subsequence](https://leetcode.com/problems/is-subsequence/description/)
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- [399 Evaluate Division](https://leetcode.com/problems/evaluate-division/description/)
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- [412 Fizz Buzz](https://leetcode.com/problems/fizz-buzz/description/)
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- [415 Add Strings](https://leetcode.com/problems/add-strings/description/)
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- [427 Construct Quad Tree](https://leetcode.com/problems/construct-quad-tree/description/)
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- [433 Minimum Genetic Mutation](https://leetcode.com/problems/minimum-genetic-mutation/description/)
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- [452 Minimum Number of Arrows to Burst Balloons](https://leetcode.com/problems/minimum-number-of-arrows-to-burst-balloons/description/)

‎awesome_python_leetcode/_415_add_strings.py‎

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class Solution:
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"""Base class for all LeetCode Problems."""
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def addStrings(self, num1: str, num2: str) -> str:
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"""
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Given two non-negative integers, num1 and num2 represented as string, return the
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sum of num1 and num2 as a string.
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You must solve the problem without using any built-in library for handling large
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integers (such as BigInteger). You must also not convert the inputs to integers
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directly.
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"""
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# Time Complexity: O(n)
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# Space Complexity: O(n)
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# Addition Rules (num1, num2) => (res, rem)
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RULES = {
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("0", "0"): ("0", "0"),
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("0", "1"): ("1", "0"),
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("0", "2"): ("2", "0"),
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("0", "3"): ("3", "0"),
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("0", "4"): ("4", "0"),
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("0", "5"): ("5", "0"),
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("0", "6"): ("6", "0"),
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("0", "7"): ("7", "0"),
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("0", "8"): ("8", "0"),
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("0", "9"): ("9", "0"),
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("1", "0"): ("1", "0"),
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("1", "1"): ("2", "0"),
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("1", "2"): ("3", "0"),
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("1", "3"): ("4", "0"),
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("1", "4"): ("5", "0"),
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("1", "5"): ("6", "0"),
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("1", "6"): ("7", "0"),
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("1", "7"): ("8", "0"),
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("1", "8"): ("9", "0"),
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("1", "9"): ("0", "1"),
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("2", "0"): ("2", "0"),
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("2", "1"): ("3", "0"),
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("2", "2"): ("4", "0"),
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("2", "3"): ("5", "0"),
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("2", "4"): ("6", "0"),
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("2", "5"): ("7", "0"),
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("2", "6"): ("8", "0"),
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("2", "7"): ("9", "0"),
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("2", "8"): ("0", "1"),
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("2", "9"): ("1", "1"),
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("3", "0"): ("3", "0"),
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("3", "1"): ("4", "0"),
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("3", "2"): ("5", "0"),
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("3", "3"): ("6", "0"),
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("3", "4"): ("7", "0"),
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("3", "5"): ("8", "0"),
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("3", "6"): ("9", "0"),
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("3", "7"): ("0", "1"),
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("3", "8"): ("1", "1"),
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("3", "9"): ("2", "1"),
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("4", "0"): ("4", "0"),
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("4", "1"): ("5", "0"),
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("4", "2"): ("6", "0"),
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("4", "3"): ("7", "0"),
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("4", "4"): ("8", "0"),
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("4", "5"): ("9", "0"),
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("4", "6"): ("0", "1"),
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("4", "7"): ("1", "1"),
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("4", "8"): ("2", "1"),
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("4", "9"): ("3", "1"),
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("5", "0"): ("5", "0"),
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("5", "1"): ("6", "0"),
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("5", "2"): ("7", "0"),
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("5", "3"): ("8", "0"),
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("5", "4"): ("9", "0"),
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("5", "5"): ("0", "1"),
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("5", "6"): ("1", "1"),
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("5", "7"): ("2", "1"),
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("5", "8"): ("3", "1"),
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("5", "9"): ("4", "1"),
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("6", "0"): ("6", "0"),
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("6", "1"): ("7", "0"),
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("6", "2"): ("8", "0"),
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("6", "3"): ("9", "0"),
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("6", "4"): ("0", "1"),
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("6", "5"): ("1", "1"),
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("6", "6"): ("2", "1"),
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("6", "7"): ("3", "1"),
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("6", "8"): ("4", "1"),
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("6", "9"): ("5", "1"),
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("7", "0"): ("7", "0"),
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("7", "1"): ("8", "0"),
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("7", "2"): ("9", "0"),
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("7", "3"): ("0", "1"),
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("7", "4"): ("1", "1"),
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("7", "5"): ("2", "1"),
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("7", "6"): ("3", "1"),
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("7", "7"): ("4", "1"),
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("7", "8"): ("5", "1"),
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("7", "9"): ("6", "1"),
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("8", "0"): ("8", "0"),
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("8", "1"): ("9", "0"),
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("8", "2"): ("0", "1"),
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("8", "3"): ("1", "1"),
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("8", "4"): ("2", "1"),
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("8", "5"): ("3", "1"),
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("8", "6"): ("4", "1"),
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("8", "7"): ("5", "1"),
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("8", "8"): ("6", "1"),
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("8", "9"): ("7", "1"),
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("9", "0"): ("9", "0"),
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("9", "1"): ("0", "1"),
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("9", "2"): ("1", "1"),
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("9", "3"): ("2", "1"),
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("9", "4"): ("3", "1"),
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("9", "5"): ("4", "1"),
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("9", "6"): ("5", "1"),
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("9", "7"): ("6", "1"),
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("9", "8"): ("7", "1"),
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("9", "9"): ("8", "1"),
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}
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# Get the smallest and largest number
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if len(num1) <= len(num2):
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smallest = num1
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largest = num2
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else:
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smallest = num2
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largest = num1
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# Add leading zeros to the smallest number
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smallest = "0" * (len(largest) - len(smallest)) + smallest
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# Loop through the digits from right to left
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result = ""
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remaining = "0"
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for n1, n2 in zip(reversed(smallest), reversed(largest)):
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# Apply the addition rules including remaining
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add, next_remaining1 = RULES[(n1, n2)]
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add, next_remaining2 = RULES[(add, remaining)]
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# Determine the next remaining value
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if next_remaining1 == "1":
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next_remaining = next_remaining1
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else:
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next_remaining = next_remaining2
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# Update the result and remaining
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result = add + result
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remaining = next_remaining
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# Add the remaining value if it's not zero
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if remaining == "1":
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result = remaining + result
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return result

‎tests/test_415_add_strings.py‎

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import pytest
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from awesome_python_leetcode._415_add_strings import Solution
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@pytest.mark.parametrize(
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argnames=["num1", "num2", "expected"],
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argvalues=[
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("11", "123", "134"),
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("456", "77", "533"),
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("0", "0", "0"),
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("9", "99", "108"),
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],
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)
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def test_func(num1: str, num2: str, expected: str):
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"""Tests the solution of a LeetCode problem."""
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num3 = Solution().addStrings(num1, num2)
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assert num3 == expected

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